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diff --git a/Homework/cs5300/homework-five/compilers_assn_5.tex b/Homework/cs5300/homework-five/compilers_assn_5.tex new file mode 100644 index 0000000..160bb9a --- /dev/null +++ b/Homework/cs5300/homework-five/compilers_assn_5.tex @@ -0,0 +1,192 @@ +% Created 2023-02-16 Thu 21:32 +% Intended LaTeX compiler: lualatex +\documentclass[11pt]{article} +\usepackage{graphicx} +\usepackage{longtable} +\usepackage{wrapfig} +\usepackage{rotating} +\usepackage[normalem]{ulem} +\usepackage{amsmath} +\usepackage{amssymb} +\usepackage{capt-of} +\usepackage{hyperref} +\notindent \notga \usepackage{ dsfont } \usepackage[utf8]{inputenc} \usepackage{amsmath} \usepackage{fontspec} \usepackage[a4paper,margin=1in,portrait]{geometry} \usepackage{fontspec} \setmonofont{DejaVu Sans Mono} +\author{Lizzy Hunt} +\date{\today} +\title{Assignment Five} +\hypersetup{ + pdfauthor={Lizzy Hunt}, + pdftitle={Assignment Five}, + pdfkeywords={}, + pdfsubject={}, + pdfcreator={Emacs 28.2 (Org mode 9.6.1)}, + pdflang={English}} +\begin{document} + +\maketitle +\setlength\parindent{0pt} + +\section{Question One} +\label{sec:org921f457} +\begin{verbatim} +N -> N a N b N + -> ε a N b N (using N -> ε) + -> ε a N a N b N b N (using N -> N a N b N) + -> ε a N a N b N a N b N b N (using N -> N a N b N) + -> ε a ε a N b N a N b N b N (using N -> ε) + -> ε a ε a ε b N a N b N b N (using N -> ε) + -> ε a ε a ε b ε a N b N b N (using N -> ε) + -> ε a ε a ε b ε a ε b N b N (using N -> ε) + -> ε a ε a ε b ε a ε b ε b N (using N -> ε) + -> ε a ε a ε b ε a ε b ε b ε (using N -> ε) + -> aababb (remove epsilons for clarity) +\end{verbatim} + + +\begin{center} +\includegraphics[width=225px]{./1.excalidraw.png} +\end{center} + +\section{Question Two} +\label{sec:org8175f4b} +\begin{verbatim} +N -> N N + -> N * N (using N -> N *) + -> (N) * N (using N -> (N)) + -> (N + N) * N (using N -> N + N) + -> (a + N) * N (using N -> a) + -> (a + a) * N (using N -> a) + -> (a + a) * a (using N -> a) +\end{verbatim} + +\section{Question Three} +\label{sec:org30f8f3d} +\begin{verbatim} +N -> b N a N + -> b ε a N (using N -> ε) + -> b ε a a N b N (using N -> a N b N) + -> b ε a a a N b N b N (using N -> a N b N) + -> b ε a a a ε b N b N (using N -> ε) + -> b ε a a a ε b ε b N (using N -> ε) + -> b ε a a a ε b ε b ε (using N -> ε) +\end{verbatim} + +\section{Question Four} +\label{sec:orgc6e6679} +\begin{verbatim} +N -> aNbN +N -> bNaN +N -> ε +\end{verbatim} + +\section{Question Five} +\label{sec:orgef2e893} +\(count(a) \neq count(b) \Rightarrow count(a) > count(b) \vee count(a) < count(b)\) + +\begin{itemize} +\item More A's than B's = G +\item Less A's than B's = L +\end{itemize} + +\begin{verbatim} +S -> G +S -> L +G -> GG +G -> EAE +L -> LL +L -> EBE +E -> aEaE +E -> bEaE +E -> ε +A -> aA +A -> a +B -> bB +B -> b +\end{verbatim} + +\section{Question Six} +\label{sec:orgfe19196} +This one we can actually create from a DFA! + +\begin{center} +\includegraphics[width=150px]{./6.excalidraw.png} +\end{center} + +\begin{verbatim} +S -> aN +N -> aM +N -> bS +M -> MM +M -> a +\end{verbatim} + +\section{Question Seven} +\label{sec:org2dfc6f9} +A grammar, S, with regular expressions in its production's bodies, after replacing any extensions on regular expressions with their corresponding algebraic equivalents as given in 3.3.5, then, we can transform S into an equivalent grammar by the following rules for nonterminals or terminals: + +\subsection{Kleene Closure} +\label{sec:orgdac51cc} +If we have a match in a production body corresponding to Kleene Closure, then we can transform it into two new productions: + +\begin{verbatim} +B* +\end{verbatim} + +is mapped to + +\begin{verbatim} +A -> ε +A -> BA +\end{verbatim} + +\subsection{Union} +\label{sec:org1941049} +If we have a match in a production body corresponding to the union operator, then we can rewrite it as two new productions: + +\begin{verbatim} +B | C +\end{verbatim} + +is mapped to + +\begin{verbatim} +A -> B +A -> C +\end{verbatim} + +\subsection{Example} +\label{sec:org0ac391e} +Consider the grammar: + +\begin{verbatim} +N -> (A | B)* +A -> aA +A -> ε +B -> bB +B -> ε +\end{verbatim} + +then we can form our first transformation by replacing N (with no need to rename since it's already the start symbol): + +\begin{verbatim} +N -> ε +N -> (A | B)N +A -> aA +A -> ε +B -> bB +B -> ε +\end{verbatim} + +which is then further reduced when we transform (A | B) + +\begin{verbatim} +N -> ε +N -> DN +D -> A +D -> B +A -> aA +A -> ε +B -> bB +B -> ε +\end{verbatim} +\end{document}
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